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Question: Trig function Sin1 and other
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• Page 1 of 1
Question: Trig function Sin1 and other
How the sin1 is normalized?
-2Pi < x < 2PI -> sin
-1 < x < 1 -> sin1
I would like to understand how it is normallized.
I have not found a solution.
-2Pi < x < 2PI -> sin
-1 < x < 1 -> sin1
I would like to understand how it is normallized.
I have not found a solution.
- Tronic
- Posts: 539
- Joined: Wed Dec 21, 2011 12:59 pm
Re: Question: Trig function Sin1 and other
0..1 for sin1 matchs 0..2*PI on regular sin
You can go below or above that range, it is always clipped to the valid range. So in general:
sin(2*PI*x) = sin1(x)
You can go below or above that range, it is always clipped to the valid range. So in general:
sin(2*PI*x) = sin1(x)
-
MyCo - Posts: 718
- Joined: Tue Jul 13, 2010 12:33 pm
- Location: Germany
Re: Question: Trig function Sin1 and other
thank you, I think I'm lost in the calculations.
- Tronic
- Posts: 539
- Joined: Wed Dec 21, 2011 12:59 pm
3 posts
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